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Q.

A real gas is subjected to an adiabatic process from (4 bar, 40L) to (6 bar, 25 L) against a constant pressure in a single step. Calculate the enthalpy change for the process (in bar litre).

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answer is 80.

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Detailed Solution

For adiabatic process $q = 0$

$Δ U = ω = - P_{e x t} (V_{2} - V_{1}) = - 6 (25 - 40) = 90 L - b a r$

Now $Δ H = Δ U + Δ (P V) = 90 + (150 - 160) = 90 - 10$

$Δ H = 80 L - b a r$

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A real gas is subjected to an adiabatic process from (4 bar, 40L) to (6 bar, 25 L) against a constant pressure in a single step. Calculate the enthalpy change for the process (in bar litre).