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Q.

A real valued function f(x)  satisfies the functional equationf(xy)=f(x)f(y)f(ax)f(a+y) where a is given consant and f(0)=1,f(2ax) is equal to

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a

f(x)

b

f(x)

c

f(x)

d

f(a)+f(ax)

answer is D.

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Detailed Solution

f(xy)=f(x)f(y)f(ax)f(a+y)

f(a0)=f(a)f(0)f(0)f(a)

f(a)=f(a)f(a)(f(0)=1)

f(a)=0

f(2ax)=f(a(xa))

=f(a)f(xa)f(0)f(x)

=0f(x)=f(x)

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