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A rectangular block of size 10 cm x 8 cm x 5 cm is kept in three different positions P, Q and R in turn as shown in the figure. In each case, the shaded area is rigidly fixed and a definite force F is applied tangentially to the opposite face to deform the block. The displacement of the upper face will be

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Same in all the three cases

Maximum in P position

Maximum in Q position

Maximum in R position

answer is C.

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Detailed Solution

$η = \frac{F / A}{x / L} \Rightarrow x = \frac{L}{η} \times \frac{F}{A}$

If $η$ and F are constant, then $x \propto \frac{L}{A}$

For maximum displacement, area at which force applied should be minimum and vertical side should be maximum. This is given in the Q position of rectangular block.

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