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Q.

A rectangular coil 6 cm long and 2 cm wide is placed in a magnetic field of 0.02 T. If the loop contains 200 turns and carries a current of 50 mA, the torque on the coil (with loop face parallel to the field) is

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a

0.024 Nm

b

2.4 × 10–4Nm

c

0.24 Nm

d

2.4 Nm

answer is A.

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Detailed Solution

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τ=niAB=200×50×10−3×12×10−4×0.02=2.4×10−4Nm

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