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A rectangular coil of 20 turns and area of cross section 25 sq. cm has a resistance of $100 Ω$ If a magnetic field which is perpendicular to the plane of coil changes at a rate of 1000 tesla per second, the current in the coil is

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1 A

50 A

0.5 A

5 A

answer is C.

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Detailed Solution

$i = \frac{e}{R} = \frac{\frac{nAdB}{dt}}{R}$

$= \frac{20 \times (25 \times 10^{- 4}) \times 1000}{100} = 0.5 A$

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