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A rectangular coil of 300 turns has an area of 25 cm × 10 cm. The coil rotates with a speed of 50 cps in a uniform magnetic field of strength 4 × 10^–2T about an axis perpendicular to the field. The peak value of the induced e.m.f is (in volt)

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3000 $π$

300 $π$

30 $π$

3 $π$

answer is D.

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Detailed Solution

Given data: Number of the turns N=300

Area A= 250 cm²

Magnetic field B= 4×10^-2T

Frequency f=50

Concept used: Induced EMF

Detailed solution:

The Induced EMF will be

$E = NAB ωsinθ \Rightarrow 300 \times 250 \times 10^{- 4} \times 4 \times 10^{- 2} \times 100 π = 3 π volts$

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