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A rectangular coil of size $6.0 cm \times 8.0 cm$ and having 50 turns is pivoted about the z-axis as shown in the figure. The coil carries an electric current of 5.0 A and a magnetic field of 2.0 T is present along the y-axis. If the side in the x-y plane makes an angle 53° with the x-axis and moment of inertia of the coil about the z-axis is $0.24 kg m^{2}$ ,then initial angular acceleration of the coil will be

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$2.0 rad / S^{2}$

$4.0 rad / S^{2}$

$4.8 rad / S^{2}$

$8.0 rad / S^{2}$

answer is D.

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Detailed Solution

$\vec{τ} = (48 \times 10^{- 4} \times 50 \times 5 [0.8 \hat{i} - 0.6 \hat{j}] \times 2 \hat{j}) Nm$

$τ = 1.92 Nm$
$α = \frac{τ}{I} = 8 rad / s^{2}$

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