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Q.

A rectangular coil of wire of 500 turns of area 50 cm2 carries a current of 2A in a magnetic field of induction 20 gauss. If the torque on the coil is 5 × 104 dynecm, angle between (B ) and normal to plane of coil is

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a

45°

b

90°

c

30°

d

60°

answer is A.

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Detailed Solution

torque=niABsinθ = 5×104×10-7 =500×2×50×10−4×20×10−4×sinθθ=300
θ’ = 300 ; This is angle between field and plane

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