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A rectangular field is $70 m$ long and $60 m$ broad. A well of dimensions $14 m × 8 m × 6 m$ is dug outside the field and the earth dug-out from this well is spread evenly on the field. How much will the earth level rise?

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0.16m

0.26m

0.01m

0.36m

answer is A.

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Detailed Solution

It is given a rectangular field of

70 m

long and

60 m

broad and a well of dimensions

14 m × 8 m × 6 m

.
The formula for calculating the volume of the cuboid is given by

V = l × b × h

where

l

b

and

h

are the length, breadth, and height of cuboids.
Computing the volume of the well by substituting

l = 14

b = 8

and

h = 6

.
The volume of the well

= 14 m × 8 m × 6 m

⇒

The volume of the well = 672

m 3

Computing the volume of the earth dug out by substituting

l = 70

b = 60

and

h = h

⇒

The volume of the earth dug out

= 70 m × 60 m × h m

Computing the value of

h

by equating the volume of well and volume of the earth dugout.

⇒ 70 m × 60 m × h m

= 672

m 3

Simplify the expression,

h = 672 m 3 70 m × 60 m h = 0.16 m

Thus, the rise in the earth level is

0.16 m

.
Hence option (1) is correct.

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