A rectangular film of liquid is extended from (4cm × 2cm) to (5cm × 4cm). If the work done is 3 × 10^–4J, the value of the surface tension of the liquid is

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0.025Nm^–1

0.02Nm^–1

0.125Nm^–1

8.0 Nm^–1

answer is B.

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Detailed Solution

Work done $= 2 (S . A) \times (S . T) \Rightarrow W = 2 \times (ΔA) T$
$T = \frac{W}{2 (ΔA)} = \frac{3 \times 10^{- 4}}{2 \times 12 \times 10^{- 4}} = \frac{1}{8} \times 1 = 0 .125 N / m$

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