A rectangular hole of dimensions $a \times b$ is cut in horizontal bottom of large vessel. To close the hole, a cuboidal block of dimensions $b \times c \times c$ is put on it in such a way that the square faces and a diagonal plane remain vertical as shown in the figure. Now a liquid of density $ρ$ is slowly poured in the vessel. The mass m of the block be so that the hole always remains closed irrespective of the level of liquid in the vessel is $m > ρ b {(c - \frac{a}{\sqrt{x}})}^{y}$ . Find x + y?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

answer is 4.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$F_{B} \leq m g F_{B, \max} = ρ {(C - \frac{a}{\sqrt{2}})}^{2} b g ∴ ρ {(C - \frac{a}{\sqrt{2}})}^{2} b g < m g m > ρ {(C - \frac{a}{\sqrt{2}})}^{2} b$

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!