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Q.

A rectangular loop of length l (l>d) is being pulled at a constant speed v, through a region of certain thickness d, in which a uniform magnetic field B is set up. The graph between position x of the right-hand edge of the loop and the induced emf E will be
 

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a

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b

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c

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d

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answer is B.

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Detailed Solution

As x increases so \frac{dB}{dt} increases i.e. induced emf (e) is negative. When loop completely entered in the magnetic field, emf = 0
When it exit out x increases but \frac{dB}{dt} decreases i.e. e is positive

 

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