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Q.

A rectangular loop of sides 20 cm and 10 cm carries a current of 5.0 A. A uniform magnetic field of magnitude 0.2 T exists parallel to the longer side of the loop. The force and the torque acting on the loop are

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a

0.1, 0.02 N – m parallel to the shorter side

b

Zero, 0.02 N – m perpendicular to the shorter side

c

Zero, 0.02 N – m parallel to the shorter side

d

0.1, 0.02 N – m perpendicular to the shorter side

answer is A.

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Detailed Solution

τ=Bil×d⊥ =0.2×5×10×10−2×20×10−2=0.02 Nm Force = 0

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