A rectangular loop, on which a connector EF of length I slides, is lying in a perpendicular magnetic field. The induction of magnetic field is B. The resistance of the connector is R. If the connector moves with a velocity v, then the current flowing in it will be 
 

Given data: In a perpendicular magnetic field, a rectangular loop with a connection EF of length l sliding on it is located. Magnetic field induction is B. the connector’s resistance is R.

Concept used: electromagnetic induction.

Detailed solution:

The emf that is produced when a conductor moves through a magnetic field is known as a motional emf.

We know that,

$\text{ Motional emf e}=\text{Bvl}$

Circuit’s net resistance = $R+\frac{R_1{R}_2}{R_1+R_2}$

$\therefore \text{ Current through the connector, i}=\frac{\text{Bvl}}{\text{R}+\frac{{\text{R}}_1{\text{R}}_2}{{\text{R}}_1+{\text{R}}_2}}$