A rectangular metal plate has dimensions of $10 cm \times 20 cm .$ A thin film of oil separates the plate from a fixed horizontal surface. The separation between the rectangular plate and the horizontal surface is 0.2 mm. An ideal string is attached to the plate and passes over an ideal pulley to a mass m. When m = 125 gm, the metal plate moves at constant speed of 5 cm/s across the horizontal surface. Then find the coefficient of viscosity of oil in $dyne - s / {cm}^{2} (Use g = 1000 cm / s^{2})$

Question

A rectangular metal plate has dimensions of $10 cm \times 20 cm .$ A thin film of oil separates the plate from a fixed horizontal surface. The separation between the rectangular plate and the horizontal surface is 0.2 mm. An ideal string is attached to the plate and passes over an ideal pulley to a mass m. When m = 125 gm, the metal plate moves at constant speed of 5 cm/s across the horizontal surface. Then find the coefficient of viscosity of oil in $dyne - s / {cm}^{2} (Use g = 1000 cm / s^{2})$

Infinity Learn · Accepted Answer

The coefficient of viscosity is the ratio of tangential stress on top surface of film (exerted by block) to that of velocity gradient( vertically downwards) of film. Since mass m moves with constant velocity, the string exerts a force equal to mg on plate towards right. Hence oil shall exert tangential force mg on plate towards left.

$∴ η = \frac{F / A}{(v - 0) / Δ x} = \frac{125 \times 1000 / 10 \times 20}{(5 - 0) / .02} = 2.5 d y n e - s / c m^{2}$

Start JEE / NEET / Foundation preparation at rupees 99/day !!

Detailed Solution

tricks from toppers of Infinity Learn

Get Expert Academic Guidance – Connect with a Counselor Today!