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Q.

A rectangular metallic loop is moving out of a uniform magnetic field region to a field free region with a constant speed. When the loop is partially inside the magnate field, the plot of magnitude of induced emf (ε) with time (t) is given by

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a

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b

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c

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d

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answer is D.

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Detailed Solution

Faraday's Law states that the induced emf is given by:

ε=dΦBdt\varepsilon = -\frac{d\Phi_B}{dt}

where:

ΦB=BA\Phi_B = B A is the magnetic flux,

A=lxA = l x is the area inside the field (ll is the width of the loop and xx is the length inside the field),

BB is the magnetic field strength.

Since the loop is moving with a constant velocity vv:

x=x0vtx = x_0 - v t

The flux changes as:

ΦB=Blx\Phi_B = B l x

Differentiating:

ε=Bldxdt\varepsilon = B l \frac{dx}{dt}

Since dx/dt=vdx/dt = v, we get:

ε=Blv\varepsilon = B l v

This means the induced emf is constant while the loop is exiting the field.

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