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Q.

A rectangular sheet of paper 30 cm×18 cm   can be transformed into the curved surface of a right circular cylinder in two ways i.e., either by rolling the paper along its length or by rolling it along its breadth. Find the ratio of the volumes of the two cylinders thus formed.


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a

4:2

b

5:3

c

7:2

d

4:9 

answer is B.

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Detailed Solution

It is given a rectangular sheet of paper of size 30 cm×18 cm  .
Question Image (Cylinder I)
By rolling lengthwise,
Height of cylinder I( h 1 )=18   cm    Circumference of the cylinder I=30cm  
Since, the Circumference of the base of the cylinder is 2πr  .
So,
2π r 1 =30  
r 1 = 30 2π  
r 1 = 30×7 2×22  
r 1 = 105 22 cm  
Volume ( V 1 )=π r 1 2 h 1  
V 1 = 22 7 × 105 22 × 105 22 ×18c m 3   (Cylinder II)
By rolling breadthwise,
Height of cylinder II ( h 2 )   = 30 cm   Circumference of cylinder II =18cm  
Since, the Circumference of the base of the cylinder is 2πr  .
 So, 2π r 2 =18  
r 2 = 18 2π  
r 2 = 18×7 2×22  
r 2 = 63 22  cm  
Volume ( V 2 )=π r 2 2 h 2  
V 2 = 22 7 × 63 22 × 63 22 ×30c m 3  
Divide V 1   by V 2  .
  V 1 V 2 = 22 7 × 105 22 × 105 22 ×18 22 7 × 63 22 × 63 22 ×30  
V 1 V 2 = 22×105×105×18 22×63×63×30  
V 1 V 2 = 105×105×18 63×63×30  
V 1 V 2 = 198450 119070  
V 1 V 2 = 5 3  
Therefore, the Ratio of two cylinders is 5:3   .
Hence option (2) is correct.
 
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