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Q.

A rectangular surface of sides 10 cm and 15cm is placed inside a uniform electric field of 25Vm−1, such that normal to the surface makes an angle of 60° with the distance of electric field. Find the flux of electric field through the rectangular surface in  Nm2C−1

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answer is 0.19.

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Detailed Solution

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At the surface, E→=25V/m

A→=10×10−2×15×10−2=1.5×10−2m2

Now we know that   ∫ϕ=∫Eda=E⋅A=EAcos⁡θ

ϕ=EAcos⁡θ=25×1.5×10−2×cos⁡60∘=0.1875Nm2/C≅0.19Nm2/C

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