Q.

A rectangular surface of sides 10cm and 15 cm is placed inside a uniform electric field of 25Vm1, such that normal to the surface makes an angle 60o with the direction of electric field. Find the flux of electric field through the rectangular surface.

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Detailed Solution

E=25Vm1s=10×15cm2=150×104m2
θ=60,ϕ=EAcosθ=0.1875 Nm2C1

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A rectangular surface of sides 10cm and 15 cm is placed inside a uniform electric field of 25 Vm−1, such that normal to the surface makes an angle 60o with the direction of electric field. Find the flux of electric field through the rectangular surface.