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Q.

A rectangular water reservoir is 10.8 m   by 3.75 m  at the base. Water flows into it at the rate of 18 m/s   through a pipe having the cross section 7.5 cm×4.5 cm.   Find the height to which the water will rise in the reservoir in 30 minutes.


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a

9.2m

b

4.8m

c

3.2m

d

2.7m 

answer is D.

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Detailed Solution

Given a rectangular water reservoir with base 10.8 m by 3.75 m. Water flows into it at the rate of 18m/s through a pipe having the cross-section 7.5 cm x 4.5 cm.
Let the water is raised by the height h.
The volume of the cuboid is V=l×b×h  .
Then the volume of the rectangular water reservoir is,
V=l×b×h V=10.8×3.75×h V=40.5h  m 3                 ....(1)   
Also, the cross section of pipe is,
7.5×4.5 33.75  cm 2 0.003375  m 2    
The distance covered by the water.
Distance=speed  × time Distance=18×30×60 Distance=32400 m   
The volume of the water flowed in 30 minutes is, Cross section of pipe×distance covered 0.003375×32400 109.35  m 3    
Therefore, by the equation (1),
40.5h=109.35 h= 109.35 40.5 h=2.7 m   
Thus, the height to which the water will rise in the reservoir in 30minutes is 2.7m.
Therefore, option (4) is correct.
 
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