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A rectangular wooden block of dimensions 50 cm, 20 cm and 10 cm is with its larger surface in contact with a horizontal table. The amount of work done to keep the block with smaller surface in contact with the table is (d_wood = 2000kg/m³, g=10 ms^–2)

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20 J

40 J

60 J

80 J

answer is B.

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Detailed Solution

Height of block initially= 5 cm

Height of block finally= 25 cm

Change in height= 20 cm

mass of block= $2000 \times \frac{50}{100} \times \frac{20}{100} \times \frac{10}{100} = 20 K g$

Change in pot energy = $20 \times 10 \times 0.2 = 40 J$

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