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A red LED emits light at 0.1 watts uniformly around it. The amplitude of electric field of the light at a distance of 1m from the diode is

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answer is 2.

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Detailed Solution

$E_{0} = \sqrt{\frac{2 P}{4 π \in_{0} r^{2} C}}$
Where $p = 0.1 W$
$r = 1 m$
$c = 3 \times 10^{8} m s^{- 1}$
$\frac{1}{4 π \in_{0}} = 9 \times 10^{9} N C^{- 2} m^{2}$
$= 2.45 V m^{- 1}$

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