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A red solid is insoluble in water. However, it becomes soluble if some KI is added to water. Heating the red solid in a test tube results in liberation of some violet coloured fumes and droplets of a metal appear on the cooler parts of the test tube. The red solid is :

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${({NH}_{4})}_{2} {Cr}_{2} O_{7}$

${HgI}_{2}$

$HgO$

${Pb}_{3} O_{4}$

answer is B.

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Detailed Solution

${HgI}_{2}$ is water insoluble

${HgI}_{2} \overset{KI}{⟶} \underset{(Soluble)}{K_{2} {HgI}_{4} \overset{Δ}{⟶}} \underset{(Violet fumes)}{Hg + I_{2}}$

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