Q.

A reddish-brown metal ‘M’ forms two oxides like MO and M2O  which are present in black and Red color.

2M+O2MO(Black);Process'X'

4M+O22M2O(Red);Process'Y'

and sometimes the above-formed two oxides can be interconverted to one another as given below.

MO(Black)processZprocessWM2O(Red)

Then identify the process W, X, Y, and Z respectively.

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a

W-Oxidation ;  X-Oxidation

Y-Oxidation ;    Z-Oxidation

b

W-Reduction ; X-Oxidation     

Y-Oxidation ;    Z-Reduction

c

W-Reduction ;  X-Oxidation   

Y-Oxidation  ;   Z-Oxidation

d

W-Oxidation ;  X-Reduction

Y-Oxidation ;    Z-Reduction

answer is A.

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Detailed Solution

The addition of oxygen or loss of electrons is called oxidation.

The addition of hydrogen or gaining electrons is called reduction.

So, the correct answer is A.

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A reddish-brown metal ‘M’ forms two oxides like MO and M2O  which are present in black and Red color.2M+O2→MO(Black)   ;  Process  'X'4M+O2→2M2O(Red)  ;  Process  'Y'and sometimes the above-formed two oxides can be interconverted to one another as given below.MO(Black)⇌process Zprocess WM2O(Red)Then identify the process W, X, Y, and Z respectively.