A refracting (astronomical) telescope, when in normal adjustment, has a magnifying power of 6 and the objective and the eyepiece are 14 cm apart. Find the focal lengths of the lenses of the telescope.

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answer is 1.

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Detailed Solution

Given,
Magnification = 6,
Length =14.
We know,
In a telescope,

$Length of the telescope = f_{0} + f_{e} -(1) Magnification = \frac{f_{o}}{f_{e}} = 6 f_{0} = 6 f_{e} Putting in equation 1 . 6 f_{e} + f_{e} = 14 f_{e} = 2 cm f_{o} = 12 cm$

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