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Q.

A refrigerator transfer 180 joule of energy in one second from temperature - 3^oC to 27^oC. Calculate the average power consumed, assuming no energy losses in the process.

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a

18 W

b

54 W

c

20 W

d

120 W

answer is C.

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Detailed Solution

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Here,
$T_{1} = 27 + 273 = 300 K and T_{2} = - 3 + 273 = 270 K As \frac{Q_{1}}{Q_{2}} = \frac{T_{1}}{T_{2}} \Rightarrow Q_{1} = \frac{T_{1}}{T_{2}} \times Q_{2} = (\frac{300}{270}) (180) = 200 W$
Therefore,average power consumed
$= Q_{1} - Q_{2} = 200 W - 180 W = 20 W$

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