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A refrigerator works between 4° C and 30° C . It is required to remove 600 calories of heat every second in order to keep the temperature of the refrigerated space constant. The power required is (take 1 cal=4.2 Joules)

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2.365 W

23.65 W

236.5 W

2365 W

answer is C.

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Detailed Solution

$\begin{array}{l} \frac{Q_{1}}{Q_{2}} = \frac{T_{1}}{T_{2}} \Rightarrow \frac{Q_{1}}{600} = \frac{303}{273} \\ \Rightarrow Q_{1} = 656 .3 cal / S \end{array}$
Work done $W = Q_{1} - Q_{2} = 236 .4 W$

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