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Q.

A regular cube of metal measures exactly 10 cm on an edge and has density 8g/cc. If the cube contains $6 \times 10^{25}$ atoms of the metal, determine atomic weight of metal: (Take $N_{A} = 6 \times 10^{23})$

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a

100

b

60

c

40

d

80

answer is C.

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Detailed Solution

$density = \frac{mass}{volume}$

$\begin{array}{l} 8 = \frac{6 \times 10^{25} \times \frac{M}{6 \times 10^{23}}}{1000} \\ M = 80 \end{array}$

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