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A regular hexagon of side 10cm has a charge $5 μ c$ at each of its vertices calculate the potential at the centre of the hexagon

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2700 kv

2600 kv

2400 kv

2800 kv

answer is A.

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Detailed Solution

$V_{n e t} = 6 \times \frac{q}{4 π ε_{0} r} = \frac{6 \times 5 \times 10^{- 6} \times 9 \times 10^{9}}{10 \times 10^{- 2}} = 6 \times 5 \times 9 \times 10^{4} = 30 \times 9 \times 10^{4} = 270 \times 10^{4} V = 2700 K v$

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