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Q.

A resistance coil of 60 ohm is immersed in 42000 gm of water. A current of 7A is passed through it. Calculate the rise in temperature per minute. The sp. heat of  water =4200Jkg−∘K

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a

1∘C

b

2∘C

c

5∘C

d

3∘C

answer is D.

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Detailed Solution

Heat produced = Heat absorbed by water

i2Rt=mSΔθ

Δθt=i2RmS

Δθt=72×6042×4200K/s

Δθt=72×6042×4200×60K/min

Δθt=1 K/min = 1oC/min

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