A resistance coil of 60 ohm is immersed in 42000 gm of water. A current of 7A is passed through it. Calculate the rise in temperature per minute. The sp. heat of $water = 4200 \frac{J}{kg -^{\circ} K}$

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$1^{\circ} C$

$2^{\circ} C$

$5^{\circ} C$

$3^{\circ} C$

answer is D.

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Detailed Solution

Heat produced = Heat absorbed by water

$i^{2} Rt = mSΔ θ$

$\frac{Δ θ}{t} = \frac{i^{2} R}{mS}$

$\frac{Δθ}{t} = \frac{7^{2} \times 60}{42 \times 4200} K / s$

$\frac{Δθ}{t} = \frac{7^{2} \times 60}{42 \times 4200} \times 60 K / \min$

$\frac{Δθ}{t} = 1 K / \min = 1^{o} C / \min$

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