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A resistance coil of 60 $Ω$ is immersed in 42 kg of water. A current of 7A is passed through it. The rise in temperature of water per minute is

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80°C

1 °C

40 °C

12 °C

answer is C.

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Detailed Solution

$Energy released = E = i^{2} Rt; Heat gained = Q = ms (∆ T)$

$\Rightarrow (∆ T) = \frac{i^{2} Rt}{ms} = \frac{7^{2} \times 60 \times 60}{42 \times 4200} = 1 ° C$

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