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A resistance of $5 Ω$ , a capacitance of $1 μ F$ ad an inductance of 10 mH are connected in series with a source of ac of variable frequency. The frequency at which maximum current flows in the circuit is

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$\frac{5000}{π} H z$

$\frac{10^{4}}{π} H z$

$\frac{10^{3}}{π} H z$

$\frac{10^{2}}{π} H z$

answer is A.

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Detailed Solution

$f = \frac{1}{2 π \sqrt{L c}} = \frac{1}{2 π \sqrt{10 \times 10^{- 3} \times 10^{- 6}}} = \frac{10^{4}}{2 π} = \frac{5000}{π} H z$

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