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Q.

A resistance wire connected in left gap of a meter bridge balances a 10Ω resistance in the right gap at a point which divides the bridge wire in the ratio 3:2. Then the resistance of wire connected in left gap is:

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a

20Ω

b

10Ω

c

15Ω

d

5Ω

answer is A.

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Detailed Solution

Given R: S=3:2, S=10Ω
R=10(32)=15Ω

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