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A resistance wire connected in left gap of a meter bridge balances a $10 Ω$ resistance in the right gap at a point which divides the bridge wire in the ratio 3:2. If the length of the resistance wire is 1.5 m, then the length of $1 Ω$ of the resistance wire is:

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$1.0 \times 10^{- 1} m$

$1.5 \times 10^{- 1} m$

$1.5 \times 10^{- 2} m$

$1.0 \times 10^{- 2} m$

answer is A.

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Detailed Solution

Given R:S=3:2, $S = 10 Ω$

$R = 10 (\frac{3}{2}) = 15 Ω$

Length of $15 Ω$ resistance wire is 1.5m
Length of $1 Ω$ resistance wire is 0.1 m

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