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A resistance $R = 12 Ω$ is connected across a source of emf as shown in the figure. Its emf changes with time as shown in the graph. What is the heat developed in the resistance in the first 4 s?

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108 J

64 J

72 J

100 J

answer is B.

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Detailed Solution

$H = \int_{0}^{4} \frac{E^{2}}{R} d t = \int_{0}^{4} \frac{{(6 t)}^{2} d t}{12} = 64 J$

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