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A resistor develops 300 J of thermal energy in 15s, when a current of 2A is passed through it. If the current increases to 3A, the energy developed in 10s is __________ J.

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answer is 450.

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Detailed Solution

$H = i^{2} Rt$

$300 = 2^{2} x R x 15$

$\Rightarrow R = \frac{300}{60} = 5 Ω$ $Now, for i = 3 A, t = 10 s, R = 5 Ω$

$H = 3^{2} x 5 x 10 = 450 J$

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