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Q.

A resistor develops 500J of thermal energy in 20 s when a current of 1.5A is passed through it. If the current is increased from 1.5 A to 3 A, what will be the energy developed in 20s.

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a

1500 J

b

2000 J

c

500 J

d

1000 J

answer is C.

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Detailed Solution

$I^{2} R T = H \Rightarrow \frac{H_{1}}{H_{2}} = {(\frac{I_{1}}{I_{2}})}^{2} \Rightarrow H_{2} = 500 \times {(\frac{3}{3 / 2})}^{2} = 2000 J$

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