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Q.

A reversible isothermal evaporation of 90g of water is carried out at 100°C. heat of evaporation of water is 9.72 kcal/mol. Assuming water vapour to behave like an ideal gas, what is the change in internal energy of the system?

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a

44.87 kcal

b

48.6 kcal

c

52.23 kcal

d

56.06 kcal

answer is C.

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Detailed Solution

Change in enthalpy (ΔH)=heat of evaporation x number of mole  = 9.72x5

ΔH=ΔE+ΔnRTΔE=48.6-5×2×10-3×373=44.87kcal

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