A rhombus has diagonals that are 16 cm and 12 cm long, respectively. Find the length of its side.

In this case, the triangle's sides make up half of the rhombus' diagonals, and the hypotenuse of the rhombus is its side.

 Using Pythagoras's Theorem,

${\left(\frac{16}{2}\right)}^2+{\left(\frac{12}{2}\right)}^2=sid{e}^2$

$8^2+6^2=sid{e}^2$

$64+36=sid{e}^2$

side $=10 \mathrm{cm}$