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A rifle resting against a cushion fires a bullet as shown. Figure $(a)$ below shows the event before firing the bullet. After firing the bullet, the rifle compresses the cushion by $25 m m$ and comes to rest.

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The change in momentum of the bullet is $14.7 K g / m / s .$

The recoil speed of the rifle immediately after firing $3.5 m / s .$

The average force exerted by the cushion in stopping the rifle $1.03 K N .$

Work done on the is $25.73 J$

answer is A, B, C, D.

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Detailed Solution

$Δ \vec{p} = m Δ \vec{v} = 0.0525 (280 - 0) = 14.7 {kgms}^{- 1} 4.20 \times v = 14.7 \Rightarrow v = 3.5 {ms}^{- 1}$

Work done $o n t h e r i f l e = C h a n g e i n k i n e t i c e n e r g y o f t h e r i f l e = \frac{1}{2} \times 4.2 \times 3 . 5^{2} J = 25.73 J$

$F_{av} \times 0.025 = \frac{1}{2} \times 4.20 \times 3 . 5^{2}, F_{av} \approx 1.03 \times 10^{3} N$

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