A right angled isosceles triangle is inscribed in the circle x2 + y2 - 4x - 2y - 4 = 0 then length of the side of the triangle is

C=2, 1, r=4+1+4=3Let AB = AC = aΔABC is right angle isosceles Δle⇒ AB2+AC2=BC2⇒ a2+a2=2r2⇒ 2a2=4r2⇒ a2=29=18 ⇒ a=18=32

A right angled isosceles triangle is inscribed in the circle x2 + y2 - 4x - 2y - 4 = 0 then length of the side of the triangle is

C=2, 1, r=4+1+4=3Let AB = AC = aΔABC is right angle isosceles Δle⇒ AB2+AC2=BC2⇒ a2+a2=2r2⇒ 2a2=4r2⇒ a2=29=18 ⇒ a=18=32

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A right angled isosceles triangle is inscribed in the circle x²+ y²- 4x - 2y - 4 = 0 then length of the side of the triangle is

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$\sqrt{2}$

$2 \sqrt{2}$

$3 \sqrt{2}$

$4 \sqrt{2}$

answer is C.

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$C = (2, 1), r = \sqrt{4 + 1 + 4} = 3$

Let AB = AC = a
$Δ A B C$ is right angle isosceles $Δ^{l e}$

$\begin{array}{l} \Rightarrow {(A B)}^{2} + {(A C)}^{2} = {(B C)}^{2} \\ \Rightarrow a^{2} + a^{2} = {(2 r)}^{2} \\ \Rightarrow 2 a^{2} = 4 r^{2} \\ \Rightarrow a^{2} = 2 (9) = 18 \Rightarrow a = \sqrt{18} = 3 \sqrt{2} \end{array}$

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A right angled isosceles triangle is inscribed in the circle x2 + y2 - 4x - 2y - 4 = 0 then length of the side of the triangle is

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A right angled isosceles triangle is inscribed in the circle x²+ y²- 4x - 2y - 4 = 0 then length of the side of the triangle is