Q.

Question Image

A right angled isosceles triangle is inscribed in a circle of radius r. What is the area of the remaining portion of the circle?


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a

πr22

b

(π-12)r2

c

(π-1)r2

d

(π-2)r2  

answer is C.

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Detailed Solution

Given, a right angled isosceles triangle is inscribed in a circle of radius r.
Question Image Let r be the radius of the circle and a be the length of the sides that contain the right angle. The diameter of the circle is the hypotenuse of a right-angled triangle.
Pythagoras theorem states that the square of the hypotenuse side in a right-angled triangle equals the sum of the squares of the other two sides.
So, by applying pythagoras theorem, a2+a2=(2r)2.
 2a2=4r2  a=2r Remaining area = Area of circle - Area of triangle.
We know that area of a circle is πr2 and area of the triangle=12(Base)(Height).
Remaining area =πr2-12(r2)(r2) .
Remaining area =πr2-r2 Remaining area =r2(π-1) Hence, option 3 is correct.
 
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A right angled isosceles triangle is inscribed in a circle of radius r. What is the area of the remaining portion of the circle?