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Q.

A right-angled prism of apex angle 4 and refractive index 1.5 is located in front of a vertical plane mirror as shown in figure. A horizontal ray of light is falling 0n the prism. Find the total deviation produced in the light ray as it emerges 2nd time from the prism.

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a

174° CW

b

8°CW

c

180° CW

d

6° CW

answer is D.

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Detailed Solution

Deviation produced by prism it $δ_{1} = (μ - 1) A = 2^{\circ} CW$

Angle of incidence for mirror is $δ_{1}$ , to deviation produced by the mirror is

$δ_{2} = π - 2 δ_{1} = 176^{\circ} CW$

Deviation produced by the prism for 2"d refraction is $δ_{3} = 2^{\circ} ACW$

Net deviation = 174° CW

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A right-angled prism of apex angle 4 and refractive index 1.5 is located in front of a vertical plane mirror as shown in figure. A horizontal ray of light is falling 0n the prism. Find the total deviation produced in the light ray as it emerges 2nd time from the prism.