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A right angled triangular loop travelling with constant velocity (as shown in the figure) enters in uniform magnetic field (at right angle to the boundary of the field) directed into the paper. Draw the graph between induced emf ‘e’ and the distance along the perpendicular to the boundary of the field (say X) along which loop moves

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a

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b

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c

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d

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answer is C.

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Detailed Solution

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$e = \frac{- d ϕ}{d t}$

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A right angled triangular loop travelling with constant velocity (as shown in the figure) enters in uniform magnetic field (at right angle to the boundary of the field) directed into the paper. Draw the graph between induced emf ‘e’ and the distance along the perpendicular to the boundary of the field (say X) along which loop moves