Q.

A right triangular wooden block of mass M=4 kg is at rest on a smooth table as shown in the figure. Two smaller wooden cubes both of mass m=2 kg, initially at rest on the two sides of the larger block start sliding down. What is the normal force (in newton) applied by the system on the table?  (Take  g=9.8m/s2)
 

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answer is 58.8.

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Detailed Solution

The block M will be at rest, we see that both smaller cubes are applying net zero resultant horizontal force on the larger block.
So, N=Mg+mg(cos237+cos253)=Mg+mg

 

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