A rigid ball of mass m strikes a rigid wall at $60 °$ and gets reflected without loss of speed as shown in the figure. The value of impulse imparted by the wall on the ball will be

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$mv / 2$

$2 m v$

$mv / 3$

$m v$

answer is A.

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Detailed Solution

As we know that, impulse is imparted due to change in perpendicular components of momentum of bal
$J = Δ P = {mv}_{f} - {mv}_{i}$
$mv \cos 60 ° - (- mv \cos 60 °)$
$2 mv \cos 60 ° = 2 mv \times \frac{1}{2} = mv$

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