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A rigid body consists of a 3kg mass located at ${\vec{r}}_{1} = (2 \hat{i} + 5 \hat{j}) m$ and a 2kg mass located at ${\vec{r}}_{2} = (4 \hat{i} + 2 \hat{j}) m$ The position of centre of mass is

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$(\frac{14}{5} \hat{i} + \frac{19}{5} \hat{j}) m$

$(\frac{19}{5} \hat{i} + \frac{14}{5} \hat{j}) m$

$(\frac{14}{5} \hat{j} + \frac{19}{5} \hat{i}) m$

answer is B.

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Detailed Solution

${\vec{r}}_{cm} = \frac{m_{1} {\vec{r}}_{1} + m_{2} \vec{r_{2}}}{m_{1} + m_{2}}$

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