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Q.

A rigid container with thermally insulated walls contains a coil resistance   100Ω carrying current 1 A change in internal energy after 5 minutes will be

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a

0 KJ

b

20 KJ

c

10 KJ

d

30 KJ

answer is D.

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Detailed Solution

work done(dW) = heat energy produced in the resistor

dW=dU=change in internal energy

  heat energy produced in a resistor is dW=i2Rtgiven current i=1A;resistance R=100Ω;time t=5x60=300s   substitute given values in above equationheat energy produced in a resistor =1×100×300 change in internal energy =30000J change in internal energy = 30 kJ

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