A rigid square of loop of side ‘a’ and carrying current I2 is lying on a horizontal surface near a long current I1 carrying wire in the same plane as shown in figure. The net force on the loop due to the wire will be:

F=μ02πi1i2a−i1i22a×a=μ0i1i24π

A rigid square of loop of side ‘a’ and carrying current I2 is lying on a horizontal surface near a long current I1 carrying wire in the same plane as shown in figure. The net force on the loop due to the wire will be:

F=μ02πi1i2a−i1i22a×a=μ0i1i24π

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A rigid square of loop of side ‘a’ and carrying current I₂ is lying on a horizontal surface near a long current I₁ carrying wire in the same plane as shown in figure. The net force on the loop due to the wire will be:

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Repulsive and equal to $\frac{μ_{0} I_{1} I_{2}}{2 π}$

Attractive and equal to $\frac{μ_{0} I_{1} I_{2}}{3 π}$

Repulsive and equal to $\frac{μ_{0} I_{1} I_{2}}{4 π}$

Zero

answer is C.

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$F = \frac{μ_{0}}{2 π} (\frac{i_{1} i_{2}}{a} - \frac{i_{1} i_{2}}{2 a}) \times a = \frac{μ_{0} i_{1} i_{2}}{4 π}$

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A rigid square of loop of side ‘a’ and carrying current I2 is lying on a horizontal surface near a long current I1 carrying wire in the same plane as shown in figure. The net force on the loop due to the wire will be:

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A rigid square of loop of side ‘a’ and carrying current I₂ is lying on a horizontal surface near a long current I₁ carrying wire in the same plane as shown in figure. The net force on the loop due to the wire will be: