Q.

A rigid wire loop of square shape having side of length L and resistance R is moving along the x -axis with a constant velocity v0 in the plane of the paper. At  t=0, the right edge of the loop enters a region of length 3L where there is a uniform magnetic field B0  into the plane of the paper; as shown in the figure. For sufficiently large v0, the loop eventually crosses the region. Let  x be the location of the right edge of the loop. Let v(x),I(x) and F(x)  represent the velocity of the loop, current in the loop, and force on the loop, respectively, as a function of x. Counter-clockwise current is taken as positive.

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a

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b

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c

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d

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answer is C, D.

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Detailed Solution

While entering i.e.  x<L

f=ilB=B2l2vR

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a2=fm=B2l2vmR=kv=vdvdx                              [k=B2l2m]           v0vdv=k0xdxv=v0kx            f=B2l2R(V0kx)=αβx           i=(v0kx)BlR=i0γx        

For  3L>x>L  f=0  i=0  v= constant.
For  4L>x>3L
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f=ilB=B2l2vR          a=B2l2mRv=kv=vdvdx          v=v'0kx         f=α'β'.x       i=i'0γ'x

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A rigid wire loop of square shape having side of length L and resistance R is moving along the x -axis with a constant velocity v0 in the plane of the paper. At  t=0, the right edge of the loop enters a region of length 3L where there is a uniform magnetic field B0  into the plane of the paper; as shown in the figure. For sufficiently large v0, the loop eventually crosses the region. Let  x be the location of the right edge of the loop. Let v(x),I(x) and F(x)  represent the velocity of the loop, current in the loop, and force on the loop, respectively, as a function of x. Counter-clockwise current is taken as positive.